0=-49t^2+147t

Solution for 0=-49t^2+147t equation:

0=-49t^2+147t

We move all terms to the left:

0-(-49t^2+147t)=0

We add all the numbers together, and all the variables

-(-49t^2+147t)=0

We get rid of parentheses

49t^2-147t=0

a = 49; b = -147; c = 0;
Δ = b2-4ac
Δ = -1472-4·49·0
Δ = 21609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{21609}=147$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-147)-147}{2*49}=\frac{0}{98}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-147)+147}{2*49}=\frac{294}{98}
=3
$